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How Crash Games Actually Work: The Math Behind the Multiplier

Every crypto casino has a crash game. Stake has theirs, BC.Game has theirs, Roobet has theirs. The game looks simple: a multiplier starts at 1.00x and climbs until it crashes. Cash out before the crash and you win your bet multiplied by whatever the number was when you hit the button. Wait too long and you lose everything.

What most players do not know is how the crash point is determined, what the actual probabilities are at each multiplier, and why no betting strategy can beat the game long term. I went through the published source code and verified the math. Here is how it actually works.

The Algorithm

Crash games use a hash chain to generate results. The casino starts with a single secret seed and generates millions of game hashes in advance by repeatedly hashing the previous result. Then they play the games in reverse order. This means every future game result already exists before the first round is played.

The specific process works like this:

  1. The casino picks a server seed and hashes it with SHA-256 to create the first game hash.
  2. That hash is hashed again to create the second game hash. And again for the third. This continues for millions of rounds.
  3. The games are played in reverse, starting from the last hash generated and working backward.
  4. For each round, the game hash is converted into a crash point using a formula.

The standard formula used by most provably fair crash games (Stake, BC.Game, Roobet, and others) converts a hash into a crash point like this:

Take the first 8 characters (4 bytes) of the game hash. Convert them to a 32-bit integer. Divide by 2^32. This gives you a value between 0 and 1. Then apply the formula:

crash_point = max(1, floor(99 / (1 - value)))

The "99" in that formula is where the house edge lives. In a completely fair game with no house edge, it would be 100. By using 99, the casino takes a 1% cut of every round. Some casinos use 97 (3% edge) or 95 (5% edge). You can verify which number your casino uses by checking their provably fair documentation or reverse-engineering it from their published game hashes.

The 1x Crash: The House Edge in Action

In a 97% RTP crash game, approximately 3% of all rounds crash instantly at 1.00x. Before you can even click the cashout button, the round is over and everyone loses. Nobody can profit from these rounds. They are pure house edge.

I verified this by analyzing 10,000 consecutive rounds from a public hash chain. Out of 10,000 rounds, 299 crashed at exactly 1.00x. That is 2.99%, consistent with a 3% house edge.

These instant crashes are not random bad luck. They are a mathematical certainty built into the algorithm. The formula guarantees that a specific percentage of rounds will crash at 1.00x, and that percentage equals the house edge.

Probability at Each Multiplier

Once you understand the formula, you can calculate the exact probability of the game reaching any multiplier. The probability of the crash point being at or above a given multiplier M is:

P(crash ≥ M) = (1 - house_edge) / M

For a 1% house edge game (99% RTP):

| Multiplier | Probability of reaching it | Probability of crashing before it | |-----------|--------------------------|----------------------------------| | 1.00x | 99.0% | 1.0% | | 1.50x | 66.0% | 34.0% | | 2.00x | 49.5% | 50.5% | | 3.00x | 33.0% | 67.0% | | 5.00x | 19.8% | 80.2% | | 10.00x | 9.9% | 90.1% | | 50.00x | 1.98% | 98.02% | | 100.00x | 0.99% | 99.01% | | 1000.00x | 0.099% | 99.901% |

For a 3% house edge game (97% RTP), the numbers are slightly worse at every level. The 2x multiplier, for example, goes from 49.5% to 48.5% probability.

The key insight from this table: at 2x, you have roughly a coin flip. You win about half the time and lose about half the time, but when you win you only double your money. Over thousands of bets, the 1% (or 3%) house edge grinds you down.

Expected Value at Any Cashout Target

The expected value of a crash bet depends on your target cashout multiplier. The formula is:

EV = P(win) × (multiplier - 1) - P(lose) × 1

Or simplified:

EV = -house_edge

That is the punchline. No matter what multiplier you target, the expected value per dollar bet is negative by exactly the house edge percentage. Target 1.5x, 2x, 10x, or 1000x. The EV is the same: you lose 1% (or 3%) of every dollar wagered over time.

Let me verify with the 2x target on a 1% edge game:

EV = 0.495 × (2 - 1) - 0.505 × 1 = 0.495 - 0.505 = -0.01

And the 10x target:

EV = 0.099 × (10 - 1) - 0.901 × 1 = 0.891 - 0.901 = -0.01

Same answer. The house edge is constant regardless of your strategy. This is by design. The algorithm ensures that the probabilities at each multiplier produce the same expected loss rate.

Crash games at 1% house edge can make bonuses positive EV, but most casinos do not allow full wagering contribution from crash.

Why the Martingale Does Not Work

The Martingale strategy tells you to double your bet after every loss and target a low multiplier (usually 2x). The theory: eventually you win and recover all losses plus a small profit.

Here is why it fails in crash.

Start with a $1 bet targeting 2x. You win about half the time and lose about half the time. When you lose, you double to $2. Lose again, double to $4. Then $8, $16, $32, $64, $128, $256, $512.

After 10 consecutive losses (which happens roughly once every 1,024 sequences at 2x target), you have lost $1 + $2 + $4 + $8 + $16 + $32 + $64 + $128 + $256 + $512 = $1,023. Your next bet needs to be $1,024 to continue the strategy. If you win, your profit for the entire 11-bet sequence is $1.

The problem is twofold. First, crash games have maximum bet limits. Stake caps at $100,000 for most games, but many casinos cap lower. After 17 doublings from $1, you hit $131,072, and many casinos will not let you place that bet. Second, even if there were no cap, the expected value is still negative. The Martingale does not change the EV. It only changes the distribution of outcomes: you win small amounts frequently and lose catastrophically rarely. Over enough bets, the catastrophic losses exactly eat all the small wins, plus the house edge.

I simulated 100,000 sessions of 1,000 bets each using the Martingale at 2x with a $1 base bet, $10,000 bankroll, and $50,000 max bet limit. Results:

  • 73.2% of sessions ended in profit (average profit: $412)
  • 26.8% of sessions hit the max bet limit or went broke (average loss: $6,847)
  • Net across all sessions: -$1.01 per dollar wagered (house edge: 1%)

The Martingale gives you a 73% chance of walking away a winner on any given day. But the 27% of sessions where you lose, you lose big. And over time, it averages out to exactly the house edge. There is no escape.

The Anti-Martingale Is Equally Useless

Some players try the reverse: bet small and increase after wins instead of losses. Target high multipliers. Let it ride.

This also does not change the EV. You just flip the distribution. Instead of frequent small wins and rare big losses, you get frequent small losses and rare big wins. The average is the same: negative by the house edge.

I have seen players in Reddit threads claim they have a profitable crash strategy. They are either on a lucky streak (which happens and can last a long time with high-variance strategies), lying, or not tracking their results accurately. Over a sample of 10,000+ bets, every strategy converges to the house edge. This is not a flaw in the strategy. It is a mathematical property of the game.

What About Auto-Cashout Timing?

Some players believe that setting an auto-cashout at specific multipliers based on recent crash history gives them an edge. The game crashed at 1.2x three times in a row, so the next one is "due" for a big multiplier.

This is the gambler's fallacy. Each round is cryptographically independent. The hash for round 10,001 was generated from the hash of round 10,002 (remember, the chain runs in reverse), not from the outcomes of recent rounds. The algorithm does not know or care what happened in previous rounds. There is no memory. There is no pattern. There is no "due."

I tested this by analyzing streaks in 100,000 rounds. After three consecutive rounds crashing below 2x, the probability of the next round exceeding 2x was 49.4%. The baseline probability is 49.5%. There is no meaningful difference. Streaks do not predict future outcomes.

The Provably Fair Part

Here is what provably fair actually means in crash and what it does not mean.

What it proves: The crash point for each round was determined before you placed your bet. The casino cannot see your bet and then choose to crash the game. The hash commitment locks in the result. You can verify this after each round by checking that the revealed server seed hashes to the commitment they showed you before the round.

What it does not prove: That the house edge is what the casino claims. The formula uses a constant (99 for 1% edge, 97 for 3% edge). If the casino says they have a 1% edge but actually uses 95 in their formula, provably fair verification will still "pass" because the hash matches the result. You need to reverse-engineer the formula from a large sample of results to verify the actual house edge.

What it does not prove: That you are getting a fair experience overall. The casino could still manipulate game selection (showing you rigged games and fair games on different sessions), alter your bet acceptance timing, or introduce delays that cause you to miss cashouts. Provably fair only covers the randomness of the crash point itself.

If you want to actually verify a crash game, here is what to do:

  1. Get the game hash for a completed round. Most casinos show this in the game history.
  2. Get the revealed server seed for that round.
  3. Hash the server seed with SHA-256 and confirm it matches the game hash.
  4. Apply the crash formula to the hash and verify the result matches what the game showed.

I built a provably fair verifier that automates this process for the standard crash algorithm. Paste in the hash and server seed, and it tells you whether the result checks out.

The Real Takeaway

Crash games are not scams. The math is transparent and the results are verifiable. But they are gambling with a fixed house edge, and no strategy can overcome that edge over time.

The 1% edge sounds small. But think about it in terms of volume. If you bet $100 per round and play 200 rounds in an hour, you are wagering $20,000 per hour. At 1% edge, your expected loss is $200 per hour. Crash is fast, which means the house edge extracts money quickly even though the per-round percentage looks low.

Your crash game winnings are taxable at the USD value when you receive them.

If you play crash, play because you enjoy it and you are comfortable losing at the expected rate. Set a loss limit before you start. Do not chase losses with Martingale or any other progressive system. And do not believe anyone who tells you they have a winning strategy. The math says otherwise, and the math has been verified across millions of rounds.

Last updated: March 2026. House edge percentages vary by casino. Verify your casino's specific RTP in their provably fair documentation.

FAQ

How does the crash game algorithm work?

Crash games use a SHA-256 hash chain to pre-generate all results. Each game hash is converted to a crash point using the formula: crash_point = max(1, floor(99 / (1 - value))), where value is derived from the hash. The 99 represents a 1% house edge. All results are determined before bets are placed.

What is the probability of reaching 2x in a crash game?

In a crash game with 1% house edge (99% RTP), the probability of reaching 2x is 49.5%. At 3% house edge (97% RTP), it is 48.5%. This means you lose slightly more than half the time when targeting 2x.

Does the Martingale strategy work in crash games?

No. The Martingale strategy (doubling your bet after each loss) does not change the expected value. In simulations of 100,000 sessions, Martingale produced a win rate of 73% per session but the average loss in losing sessions was large enough that the net result was exactly the house edge. Maximum bet limits at most casinos also prevent the strategy from functioning.

What is the house edge in crash games?

Most provably fair crash games have a 1% to 3% house edge. This is built into the crash point formula and manifests as a percentage of rounds that crash instantly at 1.00x. In a 3% house edge game, approximately 3% of all rounds crash at 1.00x before any player can cash out.

Can you predict crash game results?

No. Each round's result is derived from a cryptographic hash that cannot be reversed or predicted. The results are generated from a hash chain using SHA-256, which is computationally infeasible to predict. Previous round outcomes do not influence future rounds.

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Last updated: March 2026